document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=948329>Question 948329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is 27 years older than his son..In 3 years he will be twice as old as his son. Calculate the age of the father and the son. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #578850 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=578850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=father's age; S=son's age<BR>\n" );
document.write( "F=S+27<BR>\n" );
document.write( "F+3=2(S+3) Substitute for F<BR>\n" );
document.write( "S+27+3=2S+6<BR>\n" );
document.write( "S+30=2S+6 Subtract S from each side.<BR>\n" );
document.write( "30=S+6 Subtract 6 from each side.<BR>\n" );
document.write( "24=S ANSWER 1: The son is 24 years old<BR>\n" );
document.write( "F=S+27=24+27=51 ANSWER 2: The father is 51 years old.<BR>\n" );
document.write( "CHECK IN three years, the father will be twice as old as the son:<BR>\n" );
document.write( "F+3=2(S+3)<BR>\n" );
document.write( "51+3=2(24+3)<BR>\n" );
document.write( "54=2(27)<BR>\n" );
document.write( "54=54  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );