document.write( "Question 948342: when 32 is subtracted from three times tracy's age the result is tracy's age, how old is tracy? .....I need step by step so I know how to do it please. thank you \n" ); document.write( "
Algebra.Com's Answer #578834 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let Tracy's age be \"x\"
\n" ); document.write( "when \"32\" is subtracted from \"3\" times Tracy's age which is \"3x\", the result is (means equal to) Tracy's age;\r
\n" ); document.write( "\n" ); document.write( "so, we have \"3x-32=x\"...solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( " \"3x-x=32\"\r
\n" ); document.write( "\n" ); document.write( " \"2x=32\"\r
\n" ); document.write( "\n" ); document.write( "\"x=32%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=16\"\r
\n" ); document.write( "\n" ); document.write( "Tracy is \"16\" years old\r
\n" ); document.write( "\n" ); document.write( "check given conditions:\r
\n" ); document.write( "\n" ); document.write( "\"3x-32=16\"
\n" ); document.write( "\"3%2A16-32=16\"
\n" ); document.write( "\"48-32=16\"
\n" ); document.write( "\"16=16\"
\n" ); document.write( "
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