document.write( "Question 80721This question is from textbook Gateways to Algebra and Geometry
\n" ); document.write( ": solve for: A:|x-2|=8 B: |x+6| =3\r
\n" ); document.write( "\n" ); document.write( "PLEASE HELP ME!!! \n" ); document.write( "

Algebra.Com's Answer #57878 by Earlsdon(6294) $\"\"$ $\"About$

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Solve for x:
\n" ); document.write( "A:
\n" ); document.write( " $\"abs%28x-2%29+=+8\"$ When you remove the absolute-value bars, you get two equations:
\n" ); document.write( " $\"x-2+=+8\"$ and $\"x-2+=+-8\"$ Add 2 to both sides of each equation.
\n" ); document.write( " $\"x+=+10\"$ and $\"x+=+-6\"$
\n" ); document.write( "Check:
\n" ); document.write( " $\"abs%2810-2%29+=+8\"$ so $\"abs%288%29+=+8\"$
\n" ); document.write( " $\"abs%28-6-2%29+=+8\"$ so $\"abs%28-8%29+=+8\"$
\n" ); document.write( "B:
\n" ); document.write( " $\"abs%28x%2B6%29+=+3\"$ Remove the absolute-value bars.
\n" ); document.write( " $\"x%2B6+=+3\"$ and $\"x%2B6+=+-3\"$ Subtract 6 from both sides of each equation.
\n" ); document.write( " $\"x+=+-3\"$ and $\"x+=+-9\"$
\n" ); document.write( "Check:
\n" ); document.write( " $\"abs%28-3%2B6%29+=+3\"$ so $\"abs%283%29+=+3\"$
\n" ); document.write( " $\"abs%28-9%2B6%29+=+3\"$ so $\"abs%28-3%29+=+3\"$ \n" ); document.write( "

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