document.write( "Question 948203: Another pilot plans to travel 300 km east, then 300 km north-east. Show that the resultant bearing is 67.5 degrees. How far east of its starting point has the plane travelled? Please Help! I am struggling! Thank You! \n" ); document.write( "

Algebra.Com's Answer #578731 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let East be positive x and North be positive y.
\n" ); document.write( "Then starting from ( $\"0\"$ , $\"0\"$ ), pilot first goes 300km East.
\n" ); document.write( "( $\"0\"$ , $\"0\"$ )+( $\"300\"$ , $\"0\"$ )=( $\"300\"$ , $\"0\"$ )
\n" ); document.write( "Then 300km NE,
\n" ); document.write( "( $\"300\"$ , $\"0\"$ )+( $\"300cos%2845%29\"$ , $\"300sin%2845%29\"$ )=( $\"300\"$ , $\"0\"$ )+( $\"212.1\"$ , $\"212.1\"$ )=( $\"512.1\"$ , $\"212.1\"$ )
\n" ); document.write( "So the plane has traveled 512.1 miles East.
\n" ); document.write( "The angle that the bearing makes with the x-axis would be found using the tangent.
\n" ); document.write( " $\"tan%28theta%29=212.1%2F512.1=0.4142\"$
\n" ); document.write( " $\"theta=22.5\"$
\n" ); document.write( "So I'm assuming that the bearing you need is from North (positive y) which would be,
\n" ); document.write( " $\"90-22.5=67.5\"$
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