document.write( "Question 80709: can you help me by solving completing the square?\r
\n" ); document.write( "\n" ); document.write( "x^2-2x-35=0
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Algebra.Com's Answer #57871 by dolly(163)\"\" \"About 
You can put this solution on YOUR website!
x^2 - 2x - 35 = 0
\n" ); document.write( "adding 35 to both the sides
\n" ); document.write( "==> x^2 - 2x = 35
\n" ); document.write( "add 1 to both the sides,
\n" ); document.write( "x^2 - 2x + 1 = 35 + 1
\n" ); document.write( "==> (x-1)^2 = 36
\n" ); document.write( "Taking square root,
\n" ); document.write( "x - 1 = +/- 6
\n" ); document.write( "==> x-1 = 6 or x-1 = -6
\n" ); document.write( "==> x = 7 0r x = -5
\n" ); document.write( "Thus x = 7 or x = -5\r
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