document.write( "Question 948191: the length of a rectangle is 6 m more than its width. The perimeter of the rectangle is 60 m. find its length and breadth. \n" ); document.write( "
Algebra.Com's Answer #578697 by Princess07(1)![]() ![]() ![]() You can put this solution on YOUR website! Representation: \n" ); document.write( "Let X be the width \n" ); document.write( "Let X+6m be the length\r \n" ); document.write( "\n" ); document.write( "Solution: \n" ); document.write( "(X)+(X+6)=60 \n" ); document.write( "2X+6=60 \n" ); document.write( "2X=54 \n" ); document.write( "X= 27m\r \n" ); document.write( "\n" ); document.write( "So, we've got the width which is 27 meters. Now lets get the length which has a measurement of X+6m.\r \n" ); document.write( "\n" ); document.write( "Substituting X= 27m to X+6m, \n" ); document.write( "27m+6m \n" ); document.write( "=33m\r \n" ); document.write( "\n" ); document.write( "Conclusion: \n" ); document.write( "Therefore, the length of the rectangle is 33m and its width is 27m. \n" ); document.write( " |