document.write( "Question 948092: The sum of three numbers is 26. Twice the first minus the second is 2 less than the third. The third is the second minus three times the first. Find the numbers and solve. \n" ); document.write( "
Algebra.Com's Answer #578656 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! The sum of three numbers is 26. Twice the first minus the second is 2 less than the third. The third is the second minus three times the first. Find the numbers and solve. \n" ); document.write( "*** \n" ); document.write( "let x=1st number \n" ); document.write( "let y=2nd number \n" ); document.write( "let z=3rd number \n" ); document.write( ".. \n" ); document.write( "x+y+z=26 (sum of three numbers is 26) \n" ); document.write( "2x-y=z-2 (Twice the first minus the second is 2 less than the third.) \n" ); document.write( "z=y-3x (The third is the second minus three times the first.) \n" ); document.write( ".. \n" ); document.write( "sub z in first 2 eq, \n" ); document.write( "x+y+y-3x=26 \n" ); document.write( "2x-y=y-3x-2 \n" ); document.write( ".. \n" ); document.write( "-2x+2y=26 \n" ); document.write( "5x-2y=-2 \n" ); document.write( "add \n" ); document.write( "3x=24 \n" ); document.write( "x=8 \n" ); document.write( "2y=5x+2=42 \n" ); document.write( "y=21 \n" ); document.write( "z=26-(x+y)=-3 \n" ); document.write( "1st number=8 \n" ); document.write( "2nd number=21 \n" ); document.write( "3rd number =-3 \n" ); document.write( " |