document.write( "Question 948092: The sum of three numbers is 26. Twice the first minus the second is 2 less than the third. The third is the second minus three times the first. Find the numbers and solve. \n" ); document.write( "
Algebra.Com's Answer #578656 by lwsshak3(11628)\"\" \"About 
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The sum of three numbers is 26. Twice the first minus the second is 2 less than the third. The third is the second minus three times the first. Find the numbers and solve.
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\n" ); document.write( "let x=1st number
\n" ); document.write( "let y=2nd number
\n" ); document.write( "let z=3rd number
\n" ); document.write( "..
\n" ); document.write( "x+y+z=26 (sum of three numbers is 26)
\n" ); document.write( "2x-y=z-2 (Twice the first minus the second is 2 less than the third.)
\n" ); document.write( "z=y-3x (The third is the second minus three times the first.)
\n" ); document.write( "..
\n" ); document.write( "sub z in first 2 eq,
\n" ); document.write( "x+y+y-3x=26
\n" ); document.write( "2x-y=y-3x-2
\n" ); document.write( "..
\n" ); document.write( "-2x+2y=26
\n" ); document.write( "5x-2y=-2
\n" ); document.write( "add
\n" ); document.write( "3x=24
\n" ); document.write( "x=8
\n" ); document.write( "2y=5x+2=42
\n" ); document.write( "y=21
\n" ); document.write( "z=26-(x+y)=-3
\n" ); document.write( "1st number=8
\n" ); document.write( "2nd number=21
\n" ); document.write( "3rd number =-3
\n" ); document.write( "
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