document.write( "Question 948119: How do I solve algebraically for all values of x:\r
\n" ); document.write( "\n" ); document.write( "log(x+3)*(2x+3)+log(x+3)*(x+5)=2\r
\n" ); document.write( "\n" ); document.write( "In this case, (x+3) is the base.
\n" ); document.write( "

Algebra.Com's Answer #578646 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
How do I solve algebraically for all values of x:
\n" ); document.write( "log(x+3)*(2x+3)+log(x+3)*(x+5)=2
\n" ); document.write( "In this case, (x+3) is the base.
\n" ); document.write( "***
\n" ); document.write( "\"log%28%28x%2B3%29%2C%282x%2B3%29%28x%2B5%29=2%29\"
\n" ); document.write( "convert to exponential form: base(x+3) raised to log of number(2)=numberz((2x+3)(x+5))
\n" ); document.write( "(x+3)^2=(2x+3)(x+5)
\n" ); document.write( "x^2+6x+9=2x^2+13x+15
\n" ); document.write( "x^2+7x+6=0
\n" ); document.write( "(x+6)(x+1)=0
\n" ); document.write( "x=-6 (reject, (x+3)<0
\n" ); document.write( "or
\n" ); document.write( "x=1
\n" ); document.write( "
\n" );