document.write( "Question 947652: a ramu tin maker converts cubical metallic box into 10 cylindrical tins.Side of the cube is 50 cm and radius of cylinder is 7 cm, find the height of each cylinder so made,if the wastage of 12% is incurred in the process. \n" ); document.write( "
Algebra.Com's Answer #578635 by KMST(5328)\"\" \"About 
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Apparently that tin maker can flatten the cubical can into and odd shaped sheet of tin with the same surface area,
\n" ); document.write( "and then manage to cut from that sheet the necessary pieces to make the 10 cylindrical cans, wasting only 12% of the material.
\n" ); document.write( "The total surface area of a cube with a \"50cm\" side is
\n" ); document.write( "\"6%2850cm%29%5E2=6%2A%282500cm%5E2%29=15000cm%5E2\" .
\n" ); document.write( "Wasting \"%2212%25%22\" means using \"%22100%25%22-%2212%25%22=%2288%25%22=88%2F100=0.88\" .
\n" ); document.write( "\"%2288%25%22\" of \"15000cm%5E2\" is
\n" ); document.write( "\"0.88%2A15000cm%5E2=13200cm%5E2\" .
\n" ); document.write( "The total surface area of a cylinder with a \"7cm\" radius and a height of \"h\"\"cm\" is
\n" ); document.write( "\"2%2Api%2A%287cm%29%5E2%2B2%2Api%2A%287cm%29%2Ah\"\"cm=2%2Api%2A7%2A%287%2Bh%29\"\"cm%5E2=14pi%2A%287%2Bh%29\"\"cm%5E2\" .
\n" ); document.write( "The total surface area of \"10\" such cylinders is
\n" ); document.write( "\"140pi%287%2Bh%29\"\"cm%5E2\" .
\n" ); document.write( "Since that is supposed to be the \"13200cm%5E2\" used, our equation is
\n" ); document.write( "\"140pi%287%2Bh%29=13200\"
\n" ); document.write( "Solving for \"h\" :
\n" ); document.write( "\"140pi%287%2Bh%29=13200\"
\n" ); document.write( "\"7%2Bh=13200%2F140pi\"
\n" ); document.write( "\"h=13200%2F140pi-7\"
\n" ); document.write( "The approximate solution is \"highlight%28h=23.012%29\"\"cm\" .
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