document.write( "Question 948045: a pan is to be formed by cutting 2cm by 2cm squares from each corner of a square piece of sheet metal and then folding the sides.if the volume of the pan is to be 441cm squared,what are the dimensions of the original piece of metal sheet? \n" ); document.write( "
Algebra.Com's Answer #578623 by ankor@dixie-net.com(22740)\"\" \"About 
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a pan is to be formed by cutting 2cm by 2cm squares from each corner of a square piece of sheet metal and then folding the sides.
\n" ); document.write( " if the volume of the pan is to be 441cm cubed,
\n" ); document.write( "what are the dimensions of the original piece of metal sheet?
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\n" ); document.write( "cutting 2cm squares from the corners will make the dimensions of the pan 4cm less than the dimensions of the original sheet metal, the height will be 2 cm
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\n" ); document.write( "Let s = the length of the side original sheet metal square
\n" ); document.write( " therefore
\n" ); document.write( "2(s-4)*(s-4) = 441
\n" ); document.write( "Foil
\n" ); document.write( "2(s^2 - 4s - 4s + 16) = 441
\n" ); document.write( "2(s^2 - 8s + 16) = 441
\n" ); document.write( "2s^2 - 16s + 32 - 441 = 0
\n" ); document.write( "2s^2 - 16s - 409 = 0
\n" ); document.write( "Use the quadratic formula to find s; a=2; b=-16; c=-409
\n" ); document.write( "I got a positive solution of
\n" ); document.write( "s = 18.85 cm is the side of the original square piece of metal
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