document.write( "Question 948079: a vending machine accepts nickels, dimes, and quarters. Exact change is needed to make a purchase. How many ways can a person with four nickels, three dimes, and two quarters make a 70 cent purchase \n" ); document.write( "
Algebra.Com's Answer #578616 by Edwin McCravy(20060) You can put this solution on YOUR website! \r\n" ); document.write( "We must use at least 1 quarter because four nickels and three dimes\r\n" ); document.write( "is only 50 cents.\r\n" ); document.write( "\r\n" ); document.write( "If we use 1 quarter, then we must make the remaining 45c\r\n" ); document.write( "with nickels and dimes. We must use all 3 dimes, because\r\n" ); document.write( "2 dimes and 4 nickels is only 40c. So 1 quarter and 3 dimes\r\n" ); document.write( "is 55c and we can make the remaining 15c with 3 ninckels.\r\n" ); document.write( "\r\n" ); document.write( "That's 1 way, \r\n" ); document.write( "\r\n" ); document.write( "1 quarter, 3 dimes and 3 nickels. \r\n" ); document.write( "\r\n" ); document.write( "If we use 2 quarters, then we must make the remaining 20c\r\n" ); document.write( "with nickels and dimes. We can use either\r\n" ); document.write( "\r\n" ); document.write( "2 quarters, 2 dimes and 0 nickels\r\n" ); document.write( "2 quarters, 1 dime and 2 nickels\r\n" ); document.write( "2 quarters, 0 dimes and 4 nickels\r\n" ); document.write( "\r\n" ); document.write( "That 3 more ways.\r\n" ); document.write( "\r\n" ); document.write( "Total: 4 ways\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |