document.write( "Question 947987: Solve the system using substitution.
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\n" ); document.write( "y = 4x - 3
\n" ); document.write( "y = 5x - 1
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\n" ); document.write( "A. (9, -4)
\n" ); document.write( "B. (5, -1)
\n" ); document.write( "C. (4, -3)
\n" ); document.write( "D. (-2, -11)
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Algebra.Com's Answer #578561 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"y+=+4x+-3\".......eq.1
\n" ); document.write( "\"y+=+5x+-1\".......eq.2
\n" ); document.write( "------------------------------substitute \"5x+-1\" for \"y\" in eq.1
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\n" ); document.write( "\"5x+-1+=+4x+-3\".......eq.1...solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"5x+-4x+=+1+-3\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x+=+-2%29\"\r
\n" ); document.write( "\n" ); document.write( "go to \"y+=+5x+-1\".......eq.2 substitute \"-2\" for \"x\" and solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+5%28-2%29+-1\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+-10+-1\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y+=+-11%29\"\r
\n" ); document.write( "\n" ); document.write( "solution is:\r
\n" ); document.write( "\n" ); document.write( "D. (\"-2\", \"-11\")\r
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