document.write( "Question 947949: A 40% solution of fertilizer is to be mixed with a 80% solution of fertilizer in order to get 40 gallons of a 70% solution. How many gallons of the 40% solution and 80% solution should be mixed? \n" ); document.write( "
Algebra.Com's Answer #578532 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Do it like this one. Only the numbers are different.
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\n" ); document.write( "Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use?
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\n" ); document.write( "e = amount of 8%
\n" ); document.write( "f = amount of 56%
\n" ); document.write( "---
\n" ); document.write( "e+ f = 8 (total solution)
\n" ); document.write( "8e + 56f = 20*8 (total saline)
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\n" ); document.write( "e+ f = 8
\n" ); document.write( "e + 7f = 20
\n" ); document.write( "------------ Subtract
\n" ); document.write( "-6f = -12
\n" ); document.write( "f = 2
\n" ); document.write( "e = 6
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