document.write( "Question 947949: A 40% solution of fertilizer is to be mixed with a 80% solution of fertilizer in order to get 40 gallons of a 70% solution. How many gallons of the 40% solution and 80% solution should be mixed? \n" ); document.write( "
Algebra.Com's Answer #578532 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Do it like this one. Only the numbers are different. \n" ); document.write( "----------- \n" ); document.write( "Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use? \n" ); document.write( "================ \n" ); document.write( "e = amount of 8% \n" ); document.write( "f = amount of 56% \n" ); document.write( "--- \n" ); document.write( "e+ f = 8 (total solution) \n" ); document.write( "8e + 56f = 20*8 (total saline) \n" ); document.write( "--- \n" ); document.write( "e+ f = 8 \n" ); document.write( "e + 7f = 20 \n" ); document.write( "------------ Subtract \n" ); document.write( "-6f = -12 \n" ); document.write( "f = 2 \n" ); document.write( "e = 6 \n" ); document.write( " |