document.write( "Question 947467: POPULATION The table shows the population for a
\n" ); document.write( "given urban area.
\n" ); document.write( "Let x be the number of years since 1950 and let y be the
\n" ); document.write( "population in thousands. Find a model for the data. Then, linearize the data and give the regression
\n" ); document.write( "equation for the linearized data.
\n" ); document.write( "Year
\n" ); document.write( "1960
\n" ); document.write( "1970
\n" ); document.write( "1980
\n" ); document.write( "1990
\n" ); document.write( "2000
\n" ); document.write( "Population (thousands)
\n" ); document.write( "30
\n" ); document.write( "58
\n" ); document.write( "120
\n" ); document.write( "220
\n" ); document.write( "455\r
\n" ); document.write( "\n" ); document.write( "I found the model of the data and it turned out to be an exponential model with an equation of y=15.198(1.07)^x. I could not find the linearized equation. The linearized equation is supposed to be y= 0.0058x+3.726
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Algebra.Com's Answer #578507 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
The data for the curve fit should be
\n" ); document.write( "(10,30)
\n" ); document.write( "(20,58)
\n" ); document.write( "(30,120)
\n" ); document.write( "(40,220)
\n" ); document.write( "(50,455)
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\n" ); document.write( "I agree with you.
\n" ); document.write( "That looks like the best fit.
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\n" ); document.write( "\n" ); document.write( "How does that linear solution even work?
\n" ); document.write( "For \"x=10\", \"y=3.784\"
\n" ); document.write( "For \"x=50\", \"y=4.016\"\r
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