document.write( "Question 80659: Lane invested $14,000, part at 15% and part at 2%. If the total inerest at the end of the year is $1,060, how much did she invest at 15%? \n" ); document.write( "

Algebra.Com's Answer #57849 by ptaylor(2198) $\"\"$ $\"About$

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Let x=amount invested at 15%\r
\n" ); document.write( "\n" ); document.write( "Then 14000-x=amount invested at 2%\r
\n" ); document.write( "\n" ); document.write( "Interest(I) equals Principal(P) times Rate(R) times Time(T) or I=PRT\r
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\n" ); document.write( "\n" ); document.write( "Now we know that total interest ($1060) equals interst at 15% (0.15x) plus interest at 2% (0.02)(14000-x). So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "1060=0.15x+0.02(14000-x) get rid of parens\r
\n" ); document.write( "\n" ); document.write( "1060=0.15x+280-0.02x subtract 280 from both sides\r
\n" ); document.write( "\n" ); document.write( "1060-280=0.15x+280-280-0.02x collect like terms\r
\n" ); document.write( "\n" ); document.write( "780=0.13x divide both sides by 0.13
\n" ); document.write( "x=$6000-------------------------------amount invested at 15%\r
\n" ); document.write( "\n" ); document.write( "14000-x=14000-6000=$8000--------------amount invested at 2%\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "6000(0.15)+8000(0.02)=1060
\n" ); document.write( "900+160=1060
\n" ); document.write( "1060=1060\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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