document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=947893>Question 947893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a perimeter of 48, the ratio of the sides is 5:4.  What is the length of the shortest side?\r<BR>\n" );
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document.write( "Simplest way to work this out, must be done only using scrap paper. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #578484 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=578484\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the ratio of the sides is 5x:4x, then<BR>\n" );
document.write( "2(5x) + 2(4x) = 48<BR>\n" );
document.write( "10x +8x = 48<BR>\n" );
document.write( "18x = 48<BR>\n" );
document.write( "3x = 8<BR>\n" );
document.write( "x = 8/3<BR>\n" );
document.write( "then the shortest side is <BR>\n" );
document.write( "4 * (8/3) = 32/3 = 10.666666667<BR>\n" );
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