document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=947891>Question 947891</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In quadrilateral abcd, ab is 4cm longer than bc. If the perimeter is 68cm howmlong must each side so that the figures is parallelogram?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #578480 by </B><A HREF=/tutors/aboutme.mpl?userid=Zucchini><B>Zucchini(70)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Zucchini><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=578480\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First of all, draw a picture and label it. Next, make the side bc \"x\". So, ab= 4+x. So, 4 + x + 4 + x + x + x = 68. Get like terms together. 8 + 4x= 68. Subtract: 4x = 60. Divide: x = 15. So, side bc is 15cm and side an is 19cm. To check, 15 +  15 + 19 + 19. It all adds up to be 68. </SPAN>\n" );
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