document.write( "Question 80671: Sally bought three chocolate bars and a pack of gum and paid $1.75. Jake bought two chocolate bars and four packs of gum and paid $2.00. Find the cost of a chocolate bar and the cost of a pack of gum. \n" ); document.write( "
Algebra.Com's Answer #57848 by ptaylor(2198) You can put this solution on YOUR website! let x=cost of chocolate bars \n" ); document.write( "and y=cost of gum\r \n" ); document.write( "\n" ); document.write( "Now we are told that 3x+y=$1.75-------------------------eq1\r \n" ); document.write( "\n" ); document.write( "We are also told that 2x+4y=$2.00-------------------------eq2\r \n" ); document.write( "\n" ); document.write( "Multiply each term in eq1 by 4 and we get:\r \n" ); document.write( "\n" ); document.write( "12x+4y=$7-----------------------------------------new eq1\r \n" ); document.write( "\n" ); document.write( "Subtract eq2 from new eq1 and we have:\r \n" ); document.write( "\n" ); document.write( "10x=$5 divide both sides by 10 \n" ); document.write( "x=$0.50----------------------------------cost of chocolate bars\r \n" ); document.write( "\n" ); document.write( "substitute x=$0.50 into eq 2:\r \n" ); document.write( "\n" ); document.write( "2($0.50)+4y=$2 get rid of parens \n" ); document.write( "$1+4y=$2 subtract $1 from both sides\r \n" ); document.write( "\n" ); document.write( "4y=$2-$1 \n" ); document.write( "4y=$1 divide both sides by 4 \n" ); document.write( "y=$0.25-----------------------------------------cost of gum\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "3($0.50)+$0.25=$1.75 \n" ); document.write( "$1.75=$1.75 \n" ); document.write( "and \n" ); document.write( "2($0.50)+4($0.25)=$2 \n" ); document.write( "$2=$2\r \n" ); document.write( "\n" ); document.write( "Hope this helps-------ptaylor \n" ); document.write( " \n" ); document.write( " |