document.write( "Question 947829: a boy is 10 years old and his mother is 37 years old. In how many years time will the mother be twice as old as her son? \n" ); document.write( "
Algebra.Com's Answer #578453 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! a boy is 10 years old and his mother is 37 years old. In how many years time \n" ); document.write( "will the mother be twice as old as her son? \n" ); document.write( " \r\n" ); document.write( "Two ways to do it. With and without algebra.\r\n" ); document.write( "\r\n" ); document.write( "Without algebra.\r\n" ); document.write( "\r\n" ); document.write( "She will be twice as old as he is when his age is the difference between their\r\n" ); document.write( "ages, which is 37-10 or 27. He will be 27 in 27-10 or 17 more years.\r\n" ); document.write( "\r\n" ); document.write( "Answer: 17 years. Checking: He'll be 27 and she'll be 54.\r\n" ); document.write( "\r\n" ); document.write( "----------------------------\r\n" ); document.write( "\r\n" ); document.write( "With algebra:\r\n" ); document.write( "\r\n" ); document.write( "In x years he will be 10+x\r\n" ); document.write( "In x years his mom will be 37+x\r\n" ); document.write( "\r\n" ); document.write( "His mom will then equal twice his age.\r\n" ); document.write( "\r\n" ); document.write( "37+x will equal 2 times 10+x.\r\n" ); document.write( "\r\n" ); document.write( "37+x = 2(10+x)\r\n" ); document.write( "\r\n" ); document.write( "37+x = 20 + 2x\r\n" ); document.write( " 17 = x\r\n" ); document.write( "\r\n" ); document.write( "Answer: 17 years. Checking: He'll be 27 and she'll be 54.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |