document.write( "Question 947824: Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two-digit number, four times the sum of its two digits is 21 less than the reversed two-digit number.
\n" ); document.write( "The difference of the original two-digit number and the number with reversed digits is
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Algebra.Com's Answer #578432 by amarjeeth123(569)\"\" \"About 
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Let the tens digit be x and the units digit be y.
\n" ); document.write( "5(x+y)=10x+y-13
\n" ); document.write( "5x=4y+13.......equation 1
\n" ); document.write( "4(x+y)=10y+x-21
\n" ); document.write( "3x=6y-21.......equation 2
\n" ); document.write( "x=2y-7.........equation 2
\n" ); document.write( "Substituting 2 in 1 we get,
\n" ); document.write( "5(2y-7)=4y+13
\n" ); document.write( "6y=48
\n" ); document.write( "y=8
\n" ); document.write( "x=16-7=9
\n" ); document.write( "The difference of the original two-digit number and the number with reversed digits is 98-89 i.e.9
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