document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=947820>Question 947820</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 ft less than twice the width, and the area of the rectangle is 14 ft squared . Find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #578424 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=578424\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be x ft.<BR>\n" );
document.write( "Then the length is (2x-3) ft.<BR>\n" );
document.write( "Area of the rectangle=x(2x-3)<BR>\n" );
document.write( "x(2x-3)=14<BR>\n" );
document.write( "2x^2-3x-14=0<BR>\n" );
document.write( "2x^2-7x+4x-14=0<BR>\n" );
document.write( "x(2x-7)+2(2x-7)=0<BR>\n" );
document.write( "(2x-7)(x+2)=0<BR>\n" );
document.write( "x=7/2=3.5 feet.<BR>\n" );
document.write( "The width is 3.5 feet and the length is 4 feet. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );