document.write( "Question 947774: Use logarithms to solve the given equation. (Round the answer to four decimal places.)
\n" ); document.write( "9(1.09^(2x + 1)) = 15
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Algebra.Com's Answer #578393 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"9%281.09%5E%282x+%2B+1%29%29+=+15\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281.09%5E%282x+%2B+1%29%29+=+15%2F9\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281.09%5E%282x+%2B+1%29%29+=+5%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%281.09%5E%282x+%2B+1%29%29%29+=log%28+5%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282x+%2B+1%29log%281.09%29+=log%28+5%29-log%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282x+%2B+1%29log%281.09%29+=log%28+5%29-log%283%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"%282x+%2B+1%29+=%28log%28+5%29-log%283%29%29%2Flog%281.09%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x++=%28log%28+5%29-log%283%29%29%2Flog%281.09%29-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x++=%28log%28+5%29-log%283%29%29%2F%282log%281.09%29%29-1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x++=%28%280.69897-0.4771%29%2F0.074853%29-0.5\"\r
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\n" ); document.write( "\n" ); document.write( "\"x++=%280.2218487496163563674912332%2F0.074853%29-0.5\"\r
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\n" ); document.write( "\n" ); document.write( "\"x++=2.9637923612461273094-0.5\"\r
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\n" ); document.write( "\n" ); document.write( "\"x++=2.4637923612461273094\"\r
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\n" ); document.write( "\n" ); document.write( "\"x++=2.4638\"\r
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