document.write( "Question 947776: Milan drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Milan drove home, there was no traffic and the trip only took 4 hours. If his average rate was 27 miles faster on the trip home, how far does Milan live from the mountains?
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document.write( "No rounding up \n" );
document.write( "
Algebra.Com's Answer #578389 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! ______________________rate___________time______________distance \n" ); document.write( "GO_____________________r_______________7_________________d \n" ); document.write( "BACK__________________r+27_____________4_________________d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"average rate was 27 miles faster on the trip home,\" \n" ); document.write( "should be \n" ); document.write( "\"average rate was 27 miles-per-hour faster on the trip home,\"\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute into the BACK equation. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |