document.write( "Question 947750: The product of two consecutive even integers is equal to 6 times the first. Find the numbers. \n" ); document.write( "

Algebra.Com's Answer #578366 by DrBeeee(684) $\"\"$ $\"About$

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let n = the first even integer.
\n" ); document.write( "Then the next even integer is n+2.
\n" ); document.write( "We are given that
\n" ); document.write( "(1) n*(n+2) = 6n or
\n" ); document.write( "(2) n*n + 2n = 6n or
\n" ); document.write( "(3) n^2 - 4n = 0 or
\n" ); document.write( "(4) n*(n - 4) = 0 which has two roots
\n" ); document.write( "(5) n = (0,4)
\n" ); document.write( "The first root n = 0 is called the trivial solution because (1) gives us 0 = 0. The solution is
\n" ); document.write( "(6) n = 4
\n" ); document.write( "Check this using (1).
\n" ); document.write( "Is (4*(4+2)=6*4)?
\n" ); document.write( "Is (4*6 = 24)?Is (24=24)? Yes
\n" ); document.write( "Answer: The two consecutive even integers are 4 and 6.
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