document.write( "Question 947602: How would I factor 7x^2-25x+12=0? \n" ); document.write( "
Algebra.Com's Answer #578247 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "to factor \"7x%5E2-25x%2B12=0\" first replace \"-25x\" with \"-21x-4x\"\r
\n" ); document.write( "\n" ); document.write( "\"7x%5E2-21x-4x%2B12=0\" ...group\r
\n" ); document.write( "\n" ); document.write( "\"%287x%5E2-21x%29-%284x-12%29=0\"...factor out \"7x\" from first group and \"4\" from second group\r
\n" ); document.write( "\n" ); document.write( "\"7x%28x-3%29-4%28x-3%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%287x-4%29%28x-3%29=0\"\r
\n" ); document.write( "\n" ); document.write( "now you can find solutions easier:\r
\n" ); document.write( "\n" ); document.write( "if \"%287x-4%29=0\"=>\"7x=4\"=>\"x=4%2F7\"\r
\n" ); document.write( "\n" ); document.write( "if \"%28x-3%29=0\"=>\"x=3\"\r
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