document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=947574>Question 947574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a circle with diameter 2700m it containing a square then what is the area of square </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #578233 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=578233\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diameter of the circle is the diagonal of the square, forming an isoceles right triangle with the diameter as hypotenuse and sides of triangle as legs.<BR>\n" );
document.write( "So <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2%2BB%5E2=C%5E2 ALIGN=MIDDLE  ALT=\"A%5E2%2BB%5E2=C%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > and in a square, A and B are equal, and C= diameter:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2%2BA%5E2=C%5E2 ALIGN=MIDDLE  ALT=\"A%5E2%2BA%5E2=C%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2A%5E2=C%5E2%29 ALIGN=MIDDLE  ALT=\"2A%5E2=C%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide each side by 2<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2=%28C%5E2%29%2F2 ALIGN=MIDDLE  ALT=\"A%5E2=%28C%5E2%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > find the square root of each side<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=sqrt%28%28C%5E2%29%2F2%29 ALIGN=MIDDLE  ALT=\"A=sqrt%28%28C%5E2%29%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=C%2Fsqrt%282%29 ALIGN=MIDDLE  ALT=\"A=C%2Fsqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and since A is the length of the side of the square and C=diameter of the circle:<BR>\n" );
document.write( "side of square (S)=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=diameter%2Fsqrt%282%29 ALIGN=MIDDLE  ALT=\"diameter%2Fsqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2700m%2Fsqrt%282%29 ALIGN=MIDDLE  ALT=\"2700m%2Fsqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Area of a square=side squared<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=S%5E2 ALIGN=MIDDLE  ALT=\"A=S%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282700m%2F%28sqrt%282%29%29%29%5E2 ALIGN=MIDDLE  ALT=\"%282700m%2F%28sqrt%282%29%29%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2700%5E2%2F2 ALIGN=MIDDLE  ALT=\"2700%5E2%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7290000%2F2 ALIGN=MIDDLE  ALT=\"7290000%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >=3645000 sq meters<BR>\n" );
document.write( "ANSWER: Area of the square is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3.645%2A10%5E6m%5E2 ALIGN=MIDDLE  ALT=\"3.645%2A10%5E6m%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >  <BR>\n" );
document.write( " </SPAN>\n" );
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