document.write( "Question 947387: If I have 200 loonies and quartres and both the coins amount equal 91.25 how many of each coin do i have
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Algebra.Com's Answer #578222 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
I guess your \"loonies\" are Canadian $1 coins. (I do not recall ever seeing one, but I have only visited Canada in very short trips).
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\n" ); document.write( "IF YOU HAVE STUDIED SYSTEMS OF LINEAR EQUATIONS:
\n" ); document.write( "\"x\"= number of loonies
\n" ); document.write( "\"y\"= number of quarters
\n" ); document.write( "\"I have 200 loonies and quarters\" translates as
\n" ); document.write( "\"x%2By=200\" .
\n" ); document.write( "Since
\n" ); document.write( "\"x\"= value of \"x\" loonies in Canadian dollars, and
\n" ); document.write( "\"0.25y=y%2F4\"= value of \"y\" quarters in Canadian dollars,
\n" ); document.write( "if the total of both types of coins amounts to 91.25,
\n" ); document.write( "\"x%2B0.25y=91.25\" or \"x%2By%2F4=91.25\" .
\n" ); document.write( "We can turn that equation into a prettier equivalent equation
\n" ); document.write( "by multiplying both sides of the equal sin times \"t\"o get
\n" ); document.write( "\"4%28x%2B0.25y%29=4%2A91.25\"<--->\"4x%2By=365\"
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\n" ); document.write( "Now we have
\n" ); document.write( "\"system%28x%2By=200%2C4x%2By=365%29\"-->\"system%28y=200-x%2C4x%2By=365%29\"-->\"system%28y=200-x%2C4x%2B200-x=365%29\"-->\"system%28y=200-x%2C3x%2B200=365%29\"-->\"system%28y=200-x%2C3x=365-200%29\"-->\"system%28y=200-x%2C3x=165%29\"-->\"system%28y=200-x%2Cx=165%2F3%29\"-->\"system%28y=200-x%2Cx=55%29\"-->\"system%28y=200-55%2Cx=55%29\"-->\"highlight%28system%28y=145%2Cx=55%29%29\"
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\n" ); document.write( "IF YOU HAVE NOT STUDIED SYSTEMS OF LINEAR EQUATIONS:
\n" ); document.write( "\"x\"= number of loonies
\n" ); document.write( "\"I have 200 loonies and quarters\" translates as
\n" ); document.write( "\"200-x\"= number of quarters.
\n" ); document.write( "Since
\n" ); document.write( "\"x\"= value of \"x\" loonies in Canadian dollars, and
\n" ); document.write( "\"0.25%28200-x%29\"= value of \"200-x\" quarters in Canadian dollars,
\n" ); document.write( "if the total of both types of coins amounts to 91.25,
\n" ); document.write( "\"x%2B0.25%28200-x%29=91.25\" .
\n" ); document.write( "Then,
\n" ); document.write( "\"x%2B0.25%28200-x%29=91.25\"-->\"x%2B50-0.25x=91.25\"-->\"x-0.25x%2B50=91.25\"-->\"x%281-0.25%29%2B50=91.25\"-->\"0.75x%2B50=91.25\"-->\"0.75x=91.25-50\"-->\"0.75x=41.25\"-->\"x=41.25%2F0.75\"-->\"highlight%28x=55%29\",
\n" ); document.write( "and \"200-x=200-55\"-->\"200-x=highlight%28145%29\" .
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\n" ); document.write( "Either way, you have \"highlight%2855%29\" loonies and \"highlight%28145%29\" quarters.
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