document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=947566>Question 947566</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Q. How much salt should be added to 60 litres of a 20% solution of salt to increase it to a 40 % solution of salt?\r<BR>\n" );
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document.write( "Do you think you can frame the equations too? How do i convert 20% of salt to measurements (ie grams or kilograms)\r<BR>\n" );
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document.write( "i was thinking (60 + x) 40/100 = ....<BR>\n" );
document.write( "Im really confused, since its a salt solution. Im in 8th grade, kindly explain in a way that is understandable to me. Thanks in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #578218 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=578218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much salt should be added to 60 litres of a 20% solution of salt to increase it to a 40 % solution of salt?<BR>\n" );
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document.write( "Add s liter of 100% salt.<BR>\n" );
document.write( "s + 60 = total liters<BR>\n" );
document.write( "100s + 60*20 = (s + 60)*40  (total salt)<BR>\n" );
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document.write( "100s + 1200 = 40s + 2400<BR>\n" );
document.write( "60s = 1200<BR>\n" );
document.write( "s = 20 liters<BR>\n" );
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