document.write( "Question 947390: 1/secA-tanA =secA+tanA
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Algebra.Com's Answer #578214 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1/secA-tanA =secA+tanA \n" ); document.write( "---- \n" ); document.write( "Multiply both sides by secA-tanA to get: \n" ); document.write( "1 = [sec^2(A)-tan^2(A)] \n" ); document.write( "--- \n" ); document.write( "1 = [1/cos^2 - sin^2/cos^2] \n" ); document.write( "---- \n" ); document.write( "1 = [1-sin^2]/cos^2 \n" ); document.write( "---- \n" ); document.write( "1 = [cos^2/cos^2] \n" ); document.write( "----- \n" ); document.write( "1 = 1 \n" ); document.write( "----------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " |