document.write( "Question 947390: 1/secA-tanA =secA+tanA
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Algebra.Com's Answer #578214 by stanbon(75887)\"\" \"About 
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1/secA-tanA =secA+tanA
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\n" ); document.write( "Multiply both sides by secA-tanA to get:
\n" ); document.write( "1 = [sec^2(A)-tan^2(A)]
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\n" ); document.write( "1 = [1/cos^2 - sin^2/cos^2]
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\n" ); document.write( "1 = [1-sin^2]/cos^2
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\n" ); document.write( "1 = [cos^2/cos^2]
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\n" ); document.write( "1 = 1
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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