document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=947548>Question 947548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car travelling at an average speed of 90km\h covers a certain distance in 4 hours.At what constent speed must the car travel to cover the same distance in 3 hours.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #578191 by </B><A HREF=/tutors/aboutme.mpl?userid=andora><B>andora(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=andora><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=578191\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since it's 90km/h we make it 90km/1hour then multiply it by 4 on two sides so it become 360km/4hours now we remove 4 hours and replace it with 3 hours and it goes like 360km/3hours which equals 120km/h <BR>\n" );
document.write( " 90km/1hour<BR>\n" );
document.write( "=360km/4hours<BR>\n" );
document.write( "=90km/h <BR>\n" );
document.write( "so<BR>\n" );
document.write( "360km/3hours<BR>\n" );
document.write( "=120km/h  </SPAN>\n" );
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