document.write( "Question 947528: Graph the circle with center at (-1, -2), which also passes through the point (0, 2). Label the center and at least four points on the circle. Write the equation of the circle \n" ); document.write( "
Algebra.Com's Answer #578189 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Graph the circle with center at (-1, -2), which also passes through the point (0, 2). Label the center and at least four points on the circle. Write the equation of the circle
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Equation of a circle: \"sqrt%28%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2%29+=+r\"
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document.write( "With the point, (0, 2), and center coordinates, or (h, k) being: (- 1, - 2), we get: 
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document.write( "\"sqrt%28%280+-+-+1%29%5E2+%2B+%282+-+-+2%29%5E2%29+=+r\"
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document.write( "\"sqrt%28%280+%2B+1%29%5E2+%2B+%282+%2B+2%29%5E2%29+=+r\"
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document.write( "\"sqrt%281+%2B+16%29+=+r\"
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document.write( "\"sqrt%2817%29+=+r\"
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document.write( "Thus, the equation becomes: \"highlight_green%28sqrt%28%28x+%2B+1%29%5E2+%2B+%28y+%2B+2%29%5E2%29+=+sqrt%2817%29%29\". Squaring both sides results in: \"%28x+%2B+1%29%5E2+%2B+%28y+%2B+2%29%5E2+=+17\"
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document.write( "When plotting this graph, you'll notice that its center is at: (- 1, - 2), it has a radius of: \"sqrt%2817%29\",
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document.write( "and one of its points is: (0, 2). This point is on its circumference, and will also be on the y-axis. 
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document.write( "Since y is 0 on the x-axis, substituting 0 for y will give you 2 more coordinate points: the x-intercepts. 
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document.write( "The 4th and final point is obtained by substituting 0 for x in the equation. This will give you the point (0, 2),
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document.write( "and another in the form of (0, y). 
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document.write( "You now have 4 points. \n" );
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