document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=947434>Question 947434</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Cary is 5 years older than Dan. In 6 years the sum of their ages will be 65. Find the age of each man now. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #578188 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=578188\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=Dan's age; C=Cary's age=D+5<BR>\n" );
document.write( "If the sum of their ages in six years will be 65, the sum is currently 65-12 (subtract 6 years for each)=53 years<BR>\n" );
document.write( "D+C=53 Substitute for C<BR>\n" );
document.write( "D+D+5=53 Subtract 5 from each side<BR>\n" );
document.write( "2D=48 Divide each side by 2<BR>\n" );
document.write( "D=24 ANSWER Dan is 24 years old.<BR>\n" );
document.write( "C=D+5=24+5=29 ANSWER 2: Cary is 29 years old<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "(D+6)+(C+6)=65<BR>\n" );
document.write( "24+6+29+6=65<BR>\n" );
document.write( "65=65  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );