document.write( "Question 947536: Selena has some nickels, dimes and quarters. She has 1½ times as many dimes as nickels. She has 5 fewer quarters than nickels. If Selena has a total of $5.05, how many of each coin does she have? \n" ); document.write( "
Algebra.Com's Answer #578185 by macston(5194)\"\" \"About 
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N=Nickels; D=Dimes=1.5N; Q=Quarters=N-5
\n" ); document.write( "$0.05N+$0.10D+$0.25Q=$5.05 Substitute for D and Q
\n" ); document.write( "$0.05N+$0.10(1.5N)+$0.25(n-5)=$5.05
\n" ); document.write( "$0.05N+$0.15N+$0.25N-$1.25=$5.05 Add $1.25 to each side
\n" ); document.write( "$0.45N=$6.30 Divide each side by $0.45
\n" ); document.write( "N=14 ANSWER 1: There are 14 nickels.
\n" ); document.write( "D=1.5N=1.5(14)=21 ANSWER 2: There are 21 dimes.
\n" ); document.write( "Q=N-5=14-5=9 ANSWER 3: There are 9 quarters
\n" ); document.write( "CHECK
\n" ); document.write( "$0.05N+$0.10D+$0.25Q=$5.05
\n" ); document.write( "$0.05(14)+$0.10(21)+$0.25(9)=$5.05
\n" ); document.write( "$0.70+$2.10+$2.25=$5.05
\n" ); document.write( "$5.05=$5.05
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