document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=947531>Question 947531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to find the y=ab^x equation for a graph that passes through the points (2,45) and (5,1215) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #578183 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=578183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Choose the base you want.  Base ten is used here.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%2810%2Cy%29=log%2810%2C%28ab%5Ex%29%29 ALIGN=MIDDLE  ALT=\"log%2810%2Cy%29=log%2810%2C%28ab%5Ex%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%2810%2Cy%29=log%2810%2Ca%29%2Bx%2Alog%2810%2Cb%29 ALIGN=MIDDLE  ALT=\"log%2810%2Cy%29=log%2810%2Ca%29%2Bx%2Alog%2810%2Cb%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28log%2810%2Cy%29=x%2Alog%2810%2Cb%29%2Blog%2810%2Ca%29%29 ALIGN=MIDDLE  ALT=\"highlight%28log%2810%2Cy%29=x%2Alog%2810%2Cb%29%2Blog%2810%2Ca%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "This equation is now in linear form.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The given points need to be reprocessed to fit with the linear formed equation.  The vertical axis coordinates must be  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%2810%2C45%29 ALIGN=MIDDLE  ALT=\"log%2810%2C45%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%2810%2C1215%29 ALIGN=MIDDLE  ALT=\"log%2810%2C1215%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The slope of the line is  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28log%2810%2Cb%29=%28log%2810%2C1215%29-log%2810%2C45%29%29%2F%285-2%29%29 ALIGN=MIDDLE  ALT=\"highlight_green%28log%2810%2Cb%29=%28log%2810%2C1215%29-log%2810%2C45%29%29%2F%285-2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Solve for b.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Slope-intercept form will still be convenient to use for find the vertical axis INTERCEPT.  Recall <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f=mx%2Bv ALIGN=MIDDLE  ALT=\"f=mx%2Bv\"   DISABLED_style= \"max-width:90%; height:auto;\" >;<BR>\n" );
document.write( "If v is for vertical axis intercept, f for the vertical axis value at any x,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=v=f-mx ALIGN=MIDDLE  ALT=\"v=f-mx\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Choose either of your treated points which fit the linearized equation, the now found slope, and solve for the value of your vertical axis intercept. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );