document.write( "Question 80633This question is from textbook
\n" ); document.write( ": We are solving quadratic equation. I tried to sole this problem, but I'm having some trouble. Please help me solve this quadratic equation: \"8x%5E3-1=0\". Any help will be appreciated. Thank you,
\n" ); document.write( " Jennie
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Algebra.Com's Answer #57818 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
solve this quadratic equation: 8x^3-1 = 0
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\n" ); document.write( "You should recognize this as \"the difference of cubes\" which come under a section
\n" ); document.write( "referred to as \"Special Factoring Formulas\", given in a book that I have as:
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\n" ); document.write( "u^3 - v^3 = (u - v)(u^2 + uv + v^2)
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\n" ); document.write( "in your problem u^3 = 8x^3 and -v^3 = -1
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\n" ); document.write( "So we have:
\n" ); document.write( "(8x^3 - 1) = (2x - 1)(4x^2 + 2x + 1)
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\n" ); document.write( "You check this for yourself: multiply (2x-1) * (4x^2 + 2x +1) you should get the
\n" ); document.write( "original equation
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\n" ); document.write( "Look in the index of your algebra book under \"difference of cubes\" you should see the special factor formulas there
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\n" ); document.write( "Added after receiving inquiry from student:
\n" ); document.write( " (2x-1)(4x^2 + 2x + 1) = 0
\n" ); document.write( "The 1st factor:
\n" ); document.write( "2x - 1 = 0
\n" ); document.write( "2x = +1
\n" ); document.write( "x = 1/2
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\n" ); document.write( "The other factor: (4x^2 + 2x + 1),= 0, has no real roots The discriminant
\n" ); document.write( "of the equation is b^2 - 4*a*c, as I am sure you know.
\n" ); document.write( "In this case, a=4; b=2; c=1: 2^2 - 4*4*1 = -12, remember when the
\n" ); document.write( "discriminant is negative it has no real roots
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\n" ); document.write( "A graph would look like this:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+8x%5E3+-+1%29+\"
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\n" ); document.write( "Note that it crosses the x axis only at +.5\r
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