document.write( "Question 80633This question is from textbook
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document.write( ": We are solving quadratic equation. I tried to sole this problem, but I'm having some trouble. Please help me solve this quadratic equation: . Any help will be appreciated. Thank you,
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document.write( " Jennie
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Algebra.Com's Answer #57818 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! solve this quadratic equation: 8x^3-1 = 0 \n" ); document.write( ": \n" ); document.write( "You should recognize this as \"the difference of cubes\" which come under a section \n" ); document.write( "referred to as \"Special Factoring Formulas\", given in a book that I have as: \n" ); document.write( ": \n" ); document.write( "u^3 - v^3 = (u - v)(u^2 + uv + v^2) \n" ); document.write( ": \n" ); document.write( "in your problem u^3 = 8x^3 and -v^3 = -1 \n" ); document.write( ": \n" ); document.write( "So we have: \n" ); document.write( "(8x^3 - 1) = (2x - 1)(4x^2 + 2x + 1) \n" ); document.write( ": \n" ); document.write( "You check this for yourself: multiply (2x-1) * (4x^2 + 2x +1) you should get the \n" ); document.write( "original equation \n" ); document.write( ": \n" ); document.write( "Look in the index of your algebra book under \"difference of cubes\" you should see the special factor formulas there \n" ); document.write( ": \n" ); document.write( "----------------------------------------------------------------- \n" ); document.write( "Added after receiving inquiry from student: \n" ); document.write( " (2x-1)(4x^2 + 2x + 1) = 0 \n" ); document.write( "The 1st factor: \n" ); document.write( "2x - 1 = 0 \n" ); document.write( "2x = +1 \n" ); document.write( "x = 1/2 \n" ); document.write( ": \n" ); document.write( "The other factor: (4x^2 + 2x + 1),= 0, has no real roots The discriminant \n" ); document.write( "of the equation is b^2 - 4*a*c, as I am sure you know. \n" ); document.write( "In this case, a=4; b=2; c=1: 2^2 - 4*4*1 = -12, remember when the \n" ); document.write( "discriminant is negative it has no real roots \n" ); document.write( ": \n" ); document.write( "A graph would look like this: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Note that it crosses the x axis only at +.5\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |