document.write( "Question 80645: x+y=5
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Algebra.Com's Answer #57817 by praseenakos@yahoo.com(507)\"\" \"About 
You can put this solution on YOUR website!
QUESTION:\r
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\n" ); document.write( "\n" ); document.write( "x+y=5
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\n" ); document.write( "\n" ); document.write( "x+y=5 --------------------(1)\r
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\n" ); document.write( "\n" ); document.write( "3x-y=7 --------------------(2)\r
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\n" ); document.write( "\n" ); document.write( "Add Equation (1) and (2)\r
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\n" ); document.write( "\n" ); document.write( "==> x + y + 3x - y = 5 + 7\r
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\n" ); document.write( "\n" ); document.write( "==> x + 3x + y - y = 12\r
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\n" ); document.write( "\n" ); document.write( "==> 4x + 0 = 12\r
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\n" ); document.write( "\n" ); document.write( "==> 4x = 12\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides of the equation by 4, then we have,\r
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\n" ); document.write( "\n" ); document.write( "4x/4 = 12/4\r
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\n" ); document.write( "\n" ); document.write( "==> x = 3\r
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\n" ); document.write( "\n" ); document.write( "Now substitute the value of x in any of the given equation.\r
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\n" ); document.write( "\n" ); document.write( "lets take equation (1)\r
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\n" ); document.write( "\n" ); document.write( "(1)==> 3 + y = 5\r
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\n" ); document.write( "\n" ); document.write( "Subtract 3 from both sides of the equation,\r
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\n" ); document.write( "\n" ); document.write( "==> 3 + y - 3 = 5 - 3 \r
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\n" ); document.write( "\n" ); document.write( "==> y = 2\r
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\n" ); document.write( "\n" ); document.write( "So the solution is x = 3 and y = 2\r
\n" ); document.write( "\n" ); document.write( "To check the solution, substitute these values in the given equations, it will satisfy the equation.\r
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\n" ); document.write( "\n" ); document.write( "Hope you understood.\r
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\n" ); document.write( "\n" ); document.write( "Regards.\r
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\n" ); document.write( "\n" ); document.write( "Praseena.\r
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