document.write( "Question 80626This question is from textbook
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document.write( ": A colony of bacteria has 6.5 X 10^6 members at 8 A.M. and 9.75 X 10^6 members at 10:30 A.M. Find its population at noon. \r
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document.write( "I used the formula N = No X 2 ^ t/d \r
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document.write( "9.75 X 10^6 = 6.5 X 10^6 X (2)^ 2.5/d \r
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document.write( "how do i work from here? \n" );
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Algebra.Com's Answer #57810 by stanbon(75887) ![]() You can put this solution on YOUR website! A colony of bacteria has 6.5 X 10^6 members at 8 A.M. and 9.75 X 10^6 members at 10:30 A.M. Find its population at noon. \n" ); document.write( "--------------------- \n" ); document.write( "Find the increase per hour: \n" ); document.write( "(9.75-6.5)/2.5 = 1.3 million per hour \n" ); document.write( "----- \n" ); document.write( "From 10:30 to noon is 1.5 hrs \n" ); document.write( "-------- \n" ); document.write( "1.3*1.5=1.95 million is the amount of increase between 10:30 and 12:00 \n" ); document.write( "--------- \n" ); document.write( "Total population will be 9.75 + 1.95 = 11.7 million \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan \n" ); document.write( " \n" ); document.write( " |