document.write( "Question 80603: An engine being tested for fuel consumption was operated at two fixed settings. The first setting results in a fuel consumption of 1 gallon every 12 minutes. The second setting results in a fuel consumption of 1 gallon every 15 minutes. The test ran 5 hours and 22 gallons of fuel were consumed. For how many minutes was the first test on the first setting? \n" ); document.write( "
Algebra.Com's Answer #57809 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! An engine being tested for fuel consumption was operated at two fixed settings. The first setting results in a fuel consumption of 1 gallon every 12 minutes. The second setting results in a fuel consumption of 1 gallon every 15 minutes. The test ran 5 hours and 22 gallons of fuel were consumed. For how many minutes was the first test on the first setting? \n" ); document.write( "--------- \n" ); document.write( "Let \"x\" minutes be be running time for the 1st setting; \n" ); document.write( "# of gallons consumed will be x/12 \n" ); document.write( "---------- \n" ); document.write( "Then \"300-x\" will be the running time for the 2nd setting: \n" ); document.write( "# of gallons consumes will be (300-x)/15 \n" ); document.write( "---------- \n" ); document.write( "EQUATION: \n" ); document.write( "gallons + gallons = 22 \n" ); document.write( "x/12 + (300-x)/15 = 22 \n" ); document.write( "Multiply thru by 60 to get: \n" ); document.write( "5x + 1200-4x = 60*22 \n" ); document.write( "x=1320-1200 \n" ); document.write( "x=120 minutes (time the 1st setting was used) \n" ); document.write( "========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |