document.write( "Question 947424: In a circle with a 12-inch radius, find the length of a segment joining the midpoint of a 20-inch chord and the center of the circle
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Algebra.Com's Answer #578087 by MathTherapy(10553)\"\" \"About 
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\n" ); document.write( "In a circle with a 12-inch radius, find the length of a segment joining the midpoint of a 20-inch chord and the center of the circle
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Two of the radii of the circle, along with the chord (base segment) form an isosceles triangle.
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document.write( "One of the congruent sides (radius of circle), the segment being sought, and \"1%2F2\" of the 20\" base,
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document.write( "or 20\" chord, form a right-triangle. Thus we have a right-triangle with hypotenuse: 12, one leg: 10,
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document.write( "and the segment joining the center of the circle, and the midpoint of the chord,  or h.
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document.write( "We then get: \"h%5E2+%2B+10%5E2+=+12%5E2\"
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document.write( "\"h%5E2+=+12%5E2+-+10%5E2\"
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document.write( "\"h%5E2+=+144+-+100\"
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document.write( "\"h%5E2+=+44\"
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document.write( "Segment joining the center of the circle, and the midpoint of the chord, or \"h+=+sqrt%2844%29\", or \"h+=+sqrt%284+%2A+11%29\", or \"highlight_green%28h+=+2sqrt%2811%29%29\" \n" );
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