document.write( "Question 947367: Problem: Determine whether the equation defines y as a function of x. Explain why or why not. \r
\n" ); document.write( "\n" ); document.write( "a.) x^2+y=9 \r
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\n" ); document.write( "\n" ); document.write( "b.) x+sqrt(y)=5
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Algebra.Com's Answer #578028 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Yes to both.\r
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\n" ); document.write( "\n" ); document.write( "#1 is obvious because you solve for y in terms of x.\r
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\n" ); document.write( "\n" ); document.write( "#2, less obvious.
\n" ); document.write( "\"x%2Bsqrt%28y%29=5\", one branch of a parabola.
\n" ); document.write( "\"sqrt%28y%29=-x%2B5\", and you must have \"y%3E=0\".
\n" ); document.write( "square both sides.
\n" ); document.write( "\"y=%285-x%29%5E2\", .\r
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\n" ); document.write( "\n" ); document.write( "The part for which y is non-negative would be the actual graph.
\n" ); document.write( "\"graph%28300%2C300%2C-8%2C12%2C-8%2C12%2C%285-x%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Also multiply the right member.
\n" ); document.write( "\"y=25-10x%2Bx%5E2\"
\n" ); document.write( "\"y=x%5E2-10x%2B25\"
\n" ); document.write( "and that is the same as \"y=%28x-5%29%5E2\".
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