document.write( "Question 947363: You drive from Fox to Nenana(60 miles) at 30 mph. At what rate would you have to drive back to fox so that the average rate for the entire trip is 60 mph. \n" ); document.write( "
Algebra.Com's Answer #578019 by josmiceli(19441) You can put this solution on YOUR website! Average rate is always ( total distance ) / ( total time ) \n" ); document.write( "The total distance is: \n" ); document.write( " \n" ); document.write( "--------------------- \n" ); document.write( "Time for Fox - Nenana trip: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--------------- \n" ); document.write( "Time for Nenana - Fox trip: \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( "---------------- \n" ); document.write( "The total time is: \n" ); document.write( " \n" ); document.write( "----------------- \n" ); document.write( "Average for the whole trip = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "There is no way you can average \n" ); document.write( "with the data given \n" ); document.write( "---------------------- \n" ); document.write( "Suppose your speed for Fox - Nenana was \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------- \n" ); document.write( "Then you end up with: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now your speed doesn't have to be infinite, \n" ); document.write( "but it is still impossible \n" ); document.write( "You have to make the trip back at \n" ); document.write( "something like \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |