document.write( "Question 80580: L has y-intercept (0, -3) and is parallel to the line with the equation y=2/3x + 1, \r
\n" ); document.write( "\n" ); document.write( "L has y-intercept (0,2) and is perpendicular to the line with equation 2x - 3y=6.
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Algebra.Com's Answer #57794 by stanbon(75887)\"\" \"About 
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L has y-intercept (0, -3) and is parallel to the line with the equation y=2/3x + 1,
\n" ); document.write( "The slope is 2/3 and the y intercept is -3.
\n" ); document.write( "So the equation is y=(2/3)x-3
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\n" ); document.write( "\n" ); document.write( "L has y-intercept (0,2) and is perpendicular to the line with equation
\n" ); document.write( "2x - 3y=6.
\n" ); document.write( "The slope of the given line is (2/3) so the slope of the perdicular line
\n" ); document.write( "must be -3/2
\n" ); document.write( "So the equation of the perpendicular line is y=(-3/2)x+2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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