document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=947205>Question 947205</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use logarithms to solve the equation\r<BR>\n" );
document.write( "\n" );
document.write( "9(1.09^2x+1)=15\r<BR>\n" );
document.write( "\n" );
document.write( "the 2x+1 is in expotential form....... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #577919 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=577919\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use logarithms to solve the equation\r<BR>\n" );
document.write( "\n" );
document.write( "9(1.09^2x+1)=15\r<BR>\n" );
document.write( "\n" );
document.write( "the 2x+1 is in expotential form  <BR>\n" );
document.write( "If you mean it's an exponent:<BR>\n" );
document.write( "================<BR>\n" );
document.write( "9(1.09^2x+1)=15<BR>\n" );
document.write( "1.09^(2x+1)= 5/3<BR>\n" );
document.write( "(2x+1)*log(1.09) = log(5/3)<BR>\n" );
document.write( "2x+1 = log(5/3)/log(1.09)<BR>\n" );
document.write( "x = (-1 + log(5/3)/log(1.09))/2\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );