document.write( "Question 947205: Use logarithms to solve the equation\r
\n" ); document.write( "\n" ); document.write( "9(1.09^2x+1)=15\r
\n" ); document.write( "\n" ); document.write( "the 2x+1 is in expotential form....... \n" ); document.write( "

Algebra.Com's Answer #577918 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"9%281.09%5E%282x%2B1%29%29=15\"$
\n" ); document.write( " $\"1.09%5E%282x%2B1%29=15%2F9\"$
\n" ); document.write( " $\"1.09%5E%282x%2B1%29=5%2F3\"$
\n" ); document.write( " $\"2x%2B1=log%281.09%2C%285%2F3%29%29\"$
\n" ); document.write( " $\"2x=log%281.09%2C%285%2F3%29%29-1\"$
\n" ); document.write( " $\"x=%281%2F2%29%28log%281.09%2C%285%2F3%29%29-1%29\"$
\n" ); document.write( " $\"highlight_green%28x=%281%2F2%29%28log%28%285%2F3%29%29%2Flog%28%281.09%29%29%29-1%2F2%29\"$
\n" ); document.write( "approximately,
\n" ); document.write( " $\"x=2.46\"$ \n" ); document.write( "

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