document.write( "Question 946203: Find the equation of the line bisecting the acute angles formed between lines
\n" ); document.write( "X+7y=6 and x-y=4.
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Algebra.Com's Answer #577882 by Fombitz(32388)\"\" \"About 
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\"x%2B7y=6\"
\n" ); document.write( "\"7y=-x%2B6\"
\n" ); document.write( "\"y=-x%2F7%2B6%2F7\"
\n" ); document.write( "\"m%5B1%5D=-1%2F7\"
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\n" ); document.write( "\"x-y=4\"
\n" ); document.write( "\"y=x-4\"
\n" ); document.write( "\"m%5B2%5D=1\"
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\n" ); document.write( "To get the angle between the two lines using the slopes use,
\n" ); document.write( "\"tan%28theta%29=abs%28%28m%5B1%5D-m%5B2%5D%29%2F%281%2Bm%5B1%5Dm%5B2%5D%29%29\"
\n" ); document.write( "\"tan%28theta%29=abs%28%281-%28-1%2F7%29%29%2F%281-1%2F7%29%29=%288%2F7%29%2F%286%2F7%29=4%2F3\"
\n" ); document.write( "So then \"theta=53.13\".
\n" ); document.write( "The line \"x-y=4\" makes a 45 degree angle with the x-axis.
\n" ); document.write( "So starting from that slope and rotating clockwise by half of 53.13 will get us to the slope of the bisector.
\n" ); document.write( "\"45-53.13%2F2=18.43\"
\n" ); document.write( "\"m=tan%2818.43%29\"
\n" ); document.write( "\"m=1%2F3\"
\n" ); document.write( "Now find the point of intersection of the two lines,
\n" ); document.write( "\"y%2B4%2B7y=6\"
\n" ); document.write( "\"8y=2\"
\n" ); document.write( "\"y=1%2F4\"
\n" ); document.write( "Then,
\n" ); document.write( "\"x-1%2F4=16%2F4\"
\n" ); document.write( "\"x=17%2F4\"
\n" ); document.write( "Now use the point-slope form of a line,
\n" ); document.write( "\"y-1%2F4=%281%2F3%29%28x-17%2F4%29\"
\n" ); document.write( "\"highlight%28y=x%2F3-7%2F6%29\"
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