document.write( "Question 947131: 1660 total they had sixteen more 10dollar bills than 50 dollar bills they had 3 more than three times as many 20 dollar bills as 50 dollar bills how many of each denomination did they have? \n" ); document.write( "
Algebra.Com's Answer #577861 by macston(5194)![]() ![]() You can put this solution on YOUR website! F=fifties; TW=twenties=3F+3; T=tens=F+16 \n" ); document.write( "$50F+$20TW+$10T=$1660 Substitute and solve for F \n" ); document.write( "$50F+$20(3F+3)+$10(F+16)=$1660 \n" ); document.write( "$50F+$60F+60+$10F+160=$1660 Subtract 220 from each side \n" ); document.write( "$120F+220-220=$1660-220 \n" ); document.write( "$120F=$1440 \n" ); document.write( "F=12 ANSWER 1: There were 12 fifty dollar bills. \n" ); document.write( "TW=3F+3=3(12)+3=36+3=39 ANSWER 2:There were 39 twenty dollar bills. \n" ); document.write( "T=F+16=12+16=28 ANSWER 3: there were 28 ten dollar bills \n" ); document.write( "CHECK \n" ); document.write( "$50F+$20TW+$10T=$1660 \n" ); document.write( "$50(12)+$20(39)+$10(28)=$1660 \n" ); document.write( "$600+$780+$280=$1660 \n" ); document.write( "$1660=$1660\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |