document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=946478>Question 946478</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I was wondering how I can translate this word problem into algebraic expression:\r<BR>\n" );
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document.write( "A rectangle has a perimeter of 20.0m. Given that it's length is 3.00 times it's breadth, find the breadth and it's area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #577836 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=577836\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let W=Width; Let L=Length=3W; Let P=Perimeter=2(L+W)=20m; Area=L*W<BR>\n" );
document.write( "Substitute for L in perimeter equation to get an equation you can solve for W:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "20m=2(3W+W)<BR>\n" );
document.write( "20m=2(4W)<BR>\n" );
document.write( "20m=8W<BR>\n" );
document.write( "2.5m=W ANSWER 1 Width (breadth)=2.5m<BR>\n" );
document.write( "Here we can find the area using width, or continue to find length (see after --OR-- below)<BR>\n" );
document.write( "AREA: METHOD 1:<BR>\n" );
document.write( "Area=L*W Substitute for L<BR>\n" );
document.write( "Area=3W*W<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=3W%5E2 ALIGN=MIDDLE  ALT=\"Area=3W%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Plug in value for W from above<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=3%282.5m%29%5E2 ALIGN=MIDDLE  ALT=\"Area=3%282.5m%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=3%286.25sqm%29 ALIGN=MIDDLE  ALT=\"Area=3%286.25sqm%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Area=18.75 sq m ANSWER 2: Area is 18.75 square meters<BR>\n" );
document.write( "  <BR>\n" );
document.write( "  --OR--\r<BR>\n" );
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document.write( "AREA: METHOD 2:<BR>\n" );
document.write( "Substitute W value in perimeter equation to find length(L):<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "20m=2(L+2.5m)<BR>\n" );
document.write( "20m=2L+5.0m Subtract 3m from each side<BR>\n" );
document.write( "15m=2L Divide each side by 2<BR>\n" );
document.write( "7.5m=L<BR>\n" );
document.write( "Find Area:<BR>\n" );
document.write( "Area=L*W=7.5m*2.5m=18.75 sq m.ANSWER 2: Area is 18.75 square meters<BR>\n" );
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