document.write( "Question 80544: Solve the equation.
\n" ); document.write( "a^2-a-2=0
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Algebra.Com's Answer #57772 by tutorcecilia(2152)\"\" \"About 
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\"%28a%5E2-a-2%29\"=0 [solve for the a-term by factoring the polynomial]
\n" ); document.write( "(a+1)(a-2)=0 [set each factor equal to zero and solve]
\n" ); document.write( "a+1=0
\n" ); document.write( "a=-1
\n" ); document.write( "and
\n" ); document.write( "a-2=0
\n" ); document.write( "a=2
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\n" ); document.write( "So, the answers are x = -1 and x=2
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\n" ); document.write( "check by plugging the values for x back into the original equation and solve.
\n" ); document.write( "\"%28a%5E2-a-2%29\"=0
\n" ); document.write( "Let x=-1
\n" ); document.write( "\"%28%28-1%29%5E2-%28-1%29-2%29\"=0
\n" ); document.write( "1+1-2=0
\n" ); document.write( "2-2=0
\n" ); document.write( "0=0 [checks out]
\n" ); document.write( "and
\n" ); document.write( "\"%28a%5E2-a-2%29\"=0
\n" ); document.write( "Let x=2
\n" ); document.write( "\"%28%282%29%5E2-%282%29-2%29\"=0
\n" ); document.write( "4-2-2=0
\n" ); document.write( "4-4-0
\n" ); document.write( "0=0 [also checks out]
\n" ); document.write( "\"%28a%5E2-a-2%29\"=0
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