document.write( "Question 946776: Two ships leaves the same port at 7 AM, the first ship sails on a 54 degree course at constant rate of 36 MPH, the second ships sails on a 144 degree course at a constant rate or 42 MPH. How far from each other are the two ships at 11 AM? \n" ); document.write( "

Algebra.Com's Answer #577647 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Two ships leaves the same port at 7 AM, the first ship sails on a 54 degree course at constant rate of 36 MPH, the second ships sails on a 144 degree course at a constant rate or 42 MPH.
\n" ); document.write( " How far from each other are the two ships at 11 AM?
\n" ); document.write( ":
\n" ); document.write( "The angle formed by the paths of the two ships: 144- 54 = 90 degrees
\n" ); document.write( "The distance between the two ships will be the hypotenuse of a right triangle
\n" ); document.write( "The travel time of the ships, 11 - 7 = 4hrs
\n" ); document.write( "The distance traveled by the two ships: Dist = speed * time
\n" ); document.write( "36 * 4 = 144 miles
\n" ); document.write( "and
\n" ); document.write( "42 * 4 = 168 miles
\n" ); document.write( "d = $\"sqrt%28144%5E2+%2B+168%5E2%29\"$
\n" ); document.write( "d = 221.27 mi apart \n" ); document.write( "

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