document.write( "Question 946856: A rectangular piece of metal is 15 inches longer than it is wide. Square with sides 3 inches long are cut from the four corners and the flaps are folded upward and taped to form an open-topped box. If the volume of the box is 648 cubic inches, what was the original width (shorter side) of the piece of metal? \n" ); document.write( "
Algebra.Com's Answer #577645 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! Just to begin,\r \n" ); document.write( "\n" ); document.write( "w, the width \n" ); document.write( "L, the length \n" ); document.write( "L=w+15 \n" ); document.write( "h, the side length of the squares cut out \n" ); document.write( "h=3 \n" ); document.write( "v, the volume of the box when the flaps folded \n" ); document.write( "v=648 \n" ); document.write( "The only true unknown here is the width, w.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The bottom area will be \n" ); document.write( "The volume will be \n" ); document.write( "Substitute for L, and simplify. This should be a quadratic equation in the symbolic form with w being the only unknown variable. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You would solve the resulting quadratic equation in w, and plugin the known values any time you are ready. \n" ); document.write( " |