document.write( "Question 946856: A rectangular piece of metal is 15 inches longer than it is wide. Square with sides 3 inches long are cut from the four corners and the flaps are folded upward and taped to form an open-topped box. If the volume of the box is 648 cubic inches, what was the original width (shorter side) of the piece of metal? \n" ); document.write( "
Algebra.Com's Answer #577645 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Just to begin,\r
\n" ); document.write( "\n" ); document.write( "w, the width
\n" ); document.write( "L, the length
\n" ); document.write( "L=w+15
\n" ); document.write( "h, the side length of the squares cut out
\n" ); document.write( "h=3
\n" ); document.write( "v, the volume of the box when the flaps folded
\n" ); document.write( "v=648
\n" ); document.write( "The only true unknown here is the width, w.\r
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\n" ); document.write( "\n" ); document.write( "The bottom area will be \"%28w-2h%29%28L-2h%29=wL-2Lh-2wh%2B4h%5E2\";
\n" ); document.write( "The volume will be \"%28wL-2Lh-2wh%2B4h%5E2%29%2Ah=v\";
\n" ); document.write( "Substitute for L, and simplify. This should be a quadratic equation in the symbolic form with w being the only unknown variable. \r
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\n" ); document.write( "\n" ); document.write( "You would solve the resulting quadratic equation in w, and plugin the known values any time you are ready.
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